JEE Main and Advanced Chemistry MCQs - Coordination Compounds and d-Block (Set 5)

JEE Main and Advanced Chemistry MCQs - Coordination Compounds and d-Block (Set 5) - CodingHumans

Coordination compounds and the d- and p-block elements make up a large part of JEE inorganic chemistry. This set covers IUPAC naming, coordination number and oxidation state, structural and geometrical isomerism, crystal field theory, spin-only magnetic moment and EAN, then lanthanoid contraction, KMnO₄ and key p-block trends.

How to practise: read each question and tap the option you think is correct. You will see right away whether you got it, along with a short explanation, and your score is tracked at the bottom of the screen. This set has 15 questions.

Topics covered in this set

  • IUPAC naming of complexes
  • Coordination number, oxidation state and EAN
  • Structural and geometrical isomerism
  • Crystal field theory and spectrochemical series
  • Magnetic moment μ = √n(n+2) BM
  • Lanthanoid contraction and p-block trends

JEE Chemistry MCQs with answers and explanations

Q1. What is the IUPAC name of [Co(NH₃)₅Cl]Cl₂?

a) Pentaamminechloridocobalt(III) chloride

b) Pentaamminecobalt(III) trichloride

c) Chloridopentaamminecobalt(II) chloride

d) Pentaamminechloridocobalt(II) dichloride

Q2. What are the oxidation state and coordination number of iron in K₃[Fe(CN)₆]?

a) +2 and 6

b) +3 and 6

c) +3 and 3

d) +6 and 6

Q3. One mole of CoCl₃·6NH₃ gives 3 mol of AgCl with excess AgNO₃. What is its correct formula?

a) [Co(NH₃)₄Cl₂]Cl

b) [Co(NH₃)₃Cl₃]

c) [Co(NH₃)₆]Cl₃

d) [Co(NH₃)₅Cl]Cl₂

Q4. [Co(NH₃)₅Br]SO₄ and [Co(NH₃)₅(SO₄)]Br are examples of:

a) Linkage isomerism

b) Coordination isomerism

c) Ionisation isomerism

d) Geometrical isomerism

Q5. How many geometrical isomers does the square planar complex [Pt(NH₃)₂Cl₂] have?

a) 4

b) 2

c) 1

d) 3

Q6. An octahedral complex of the type [MA₃B₃] shows which pair of geometrical isomers?

a) cis and trans

b) fac and mer

c) syn and anti

d) d and l

Q7. Which ligand produces the largest crystal field splitting?

a) F⁻

b) H₂O

c) CN⁻

d) I⁻

Q8. What is the spin-only magnetic moment of [Fe(H₂O)₆]²⁺?

a) 0 BM

b) 2.83 BM

c) 5.92 BM

d) 4.90 BM

Q9. Why is [Fe(CN)₆]⁴⁻ diamagnetic?

a) It is tetrahedral

b) CN⁻ is a strong-field ligand that pairs all six d electrons in t₂g

c) Fe is in the +3 state

d) It has an odd number of electrons

Q10. Which ion has a spin-only magnetic moment of about 5.92 BM?

a) Mn²⁺

b) Cu²⁺

c) Zn²⁺

d) Cr³⁺

Q11. What is the effective atomic number (EAN) of iron in K₄[Fe(CN)₆]? (Fe: Z = 26)

a) 36

b) 34

c) 38

d) 30

Q12. What are the hybridisation and magnetic nature of [Ni(CN)₄]²⁻?

a) dsp², diamagnetic

b) sp³, paramagnetic

c) sp³, diamagnetic

d) dsp², paramagnetic

Q13. Zirconium (4d) and hafnium (5d) have almost identical atomic radii because of:

a) Screening by s electrons

b) Inert pair effect

c) Diagonal relationship

d) Lanthanoid contraction

Q14. In acidic medium, how many electrons does one MnO₄⁻ ion accept when it is reduced?

a) 5

b) 3

c) 1

d) 7

Q15. Which statement about group 14 elements is correct?

a) All elements prefer the +2 state equally

b) The +2 state becomes more stable down the group because of the inert pair effect

c) Carbon shows the highest tendency to form the +2 state

d) Pb⁴⁺ is more stable than Pb²⁺

Quick revision notes

  • Name ligands alphabetically, then metal with oxidation state; anionic complexes end in -ate.
  • Spin-only μ = √n(n+2) BM: n = 1, 2, 3, 4, 5 gives 1.73, 2.83, 3.87, 4.90, 5.92.
  • Strong-field ligands (CN⁻, CO) give low-spin complexes; Δt ≈ (4/9)Δo.
  • EAN = Z − oxidation state + 2 × CN.
  • Lanthanoid contraction makes Zr ≈ Hf; inert pair effect stabilises Pb²⁺, Tl⁺, Bi³⁺.

Frequently asked questions

Are these JEE previous year questions?

No, they are original practice questions written to the NCERT-based JEE Main syllabus and level.

How do I decide high spin or low spin?

Compare Δo with the pairing energy. Strong-field ligands make Δo larger than the pairing energy, so electrons pair in t₂g first (low spin).

Why are most tetrahedral complexes high spin?

Δt is only about four-ninths of Δo, which is almost always smaller than the pairing energy.

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